Then, the reversible work that gave rise to that expansion is found using the ideal gas law for the pressure: wrev = 2V 1 V 1 nRT V dV = nRT ln(2V 1 V 1) = nRT ln2 = 1.00 mols 8.314472 J/mol K 298.15 K ln2 = 1718.28 J So, the heat flowing in to perform that expansion would be qrev = wrev = +1718.28 J Answer link The change in enthalpy of a reaction is a measure of the differences in enthalpy of the reactants and products. For example, a large fire produces more heat than a single match, even though the chemical reactionthe combustion of woodis the same in both cases. If the reaction is carried out in a closed system that is maintained at constant pressure by a movable piston, the piston will rise as nitrogen dioxide gas is formed (Figure \(\PageIndex{1}\)). If 4 mol of Al and 2 mol of Fe2O3 react, the change in enthalpy is 2 (851.5 kJ) = 1703 kJ. n H. If the substance is in solid state only, write T, If the substance is in liquid state only, write T, If the substance is in gaseous state only, write T, If the substance passes through two, three or four stages, write 0 instead of the specific heat of the phase in which the substance doesn't get through, If the substance cools down, switch the values of T. Unless otherwise specified, all reactions in this material are assumed to take place at constant pressure. The magnitude of H for a reaction is proportional to the amounts of the substances that react. But they're just as useful in dealing with physical changes, like freezing and melting, evaporating and condensing, and others. At constant pressure, heat flow equals enthalpy change: If the enthalpy change listed for a reaction is negative, then that reaction releases heat as it proceeds the reaction is exothermic (exo- = out). It is the thermodynamic unit of measurement used to determine the total amount of energy produced or released per mole in a reaction. The mass of gold is 60.0g 60.0 g. The specific heat capacity of gold is 0.129J/g C 0.129 J / g C . Our equation is: Heat Capacity = E / T. [1] When heat is absorbed, the change is said to be endothermic, and the numerical value of the heat is given a positive sign (q > 0). The reaction is highly exothermic. This video shows you how to calculate the heat absorbed or released by a system using its mass, specific heat capacity, and change in temperature.Thanks for watching! Try the plant spacing calculator. You can find the change in temperature by subtracting the starting temperature from the final temperature. Thermochemistry Worksheet 2 (Enthalpy Changes) by. You can calculate the enthalpy change in a basic way using the enthalpy of products and reactants: H=Hproducts - Hreactants. $1.50. Because the heat is absorbed by the system, the \(177.8 \: \text{kJ}\) is written as a reactant. Exothermic reactions have negative enthalpy values (-H). To find enthalpy change: All pure elements in their standard state (e.g., oxygen gas, carbon in all forms, etc.) Therefore, the overall enthalpy of the system decreases. Modified by Joshua Halpern (Howard University). Chemical reactions transform both matter and energy. As a result, the heat of a chemical reaction may be defined as the heat released into the environment or absorbed . This exchange may be either absorption of thermal energy from the atmosphere or emission of thermal energy into the atmosphere. Determine how much heat is given off when 1.00 g of H 2 reacts in the following thermochemical equation: Answer 15.1 kJ Like any stoichiometric quantity, we can start with energy and determine an amount, rather than the other way around. Then, the reversible work that gave rise to that expansion is found using the ideal gas law for the pressure: #= -"1.00 mols" xx "8.314472 J/mol"cdot"K" xx "298.15 K" xx ln 2#, So, the heat flowing in to perform that expansion would be, #color(blue)(q_(rev)) = -w_(rev) = color(blue)(+"1718.28 J")#. One way to report the heat absorbed or released would be to compile a massive set of reference tables that list the enthalpy changes for all possible chemical reactions, which would require an incredible amount of effort. The thermochemical reaction can also be written in this way: \[\ce{CH_4} \left( g \right) + 2 \ce{O_2} \left( g \right) \rightarrow \ce{CO_2} \left( g \right) + 2 \ce{H_2O} \left( l \right) \: \: \: \: \: \Delta H = -890.4 \: \text{kJ}\nonumber \]. Planning out your garden? At the end of each Thermodynamics tutorial you will find Thermodynamics revision questions with a hidden answer that reveals when clicked. For example, we can write an equation for the reaction of calcium oxide with carbon dioxide to form calcium carbonate. 002603 u and 12 u respectively. In other words, the entire energy in the universe is conserved. A chemical reaction that has a negative enthalpy is said to be exothermic. At a constant external pressure (here, atmospheric pressure). Therefore, the term 'exothermic' means that the system loses or gives up energy. To find the heat absorbed by the solution, you can use the equation hsoln = q n. BBC GCSE Bitesize: Specific Heat Capacity, The Physics Classroom: Measuring the Quantity of Heat, Georgia State University Hyper Physics: First Law of Thermodynamics, Georgia State University Hyper Physics: Specific Heat. Refer again to the combustion reaction of methane. An endothermic reaction causes absorption of heat from the surroundings. acid and a base. If you select the former: If you want to calculate the enthalpy change from the enthalpy formula: With Omni you can explore other interesting concepts of thermodynamics linked to enthalpy: try our entropy calculator and our Gibbs free energy calculator! \[\ce{CaCO_3} \left( s \right) + 177.8 \: \text{kJ} \rightarrow \ce{CaO} \left( s \right) + \ce{CO_2} \left( g \right)\nonumber \]. Second, recall that heats of reaction are proportional to the amount of substance reacting (2 mol of H2O in this case), so the calculation is. Consider, for example, a reaction that produces a gas, such as dissolving a piece of copper in concentrated nitric acid. Kylene Arnold is a freelance writer who has written for a variety of print and online publications. He + He + 4He1 C Give your answer in units of MeV. Our goal is to make science relevant and fun for everyone. In practical terms for a laboratory chemist, the system is the particular chemicals being reacted, while the surroundings is the immediate vicinity within the room. We will also explain the difference between endothermic and exothermic reactions, as well as provide you with an example of calculations. status page at https://status.libretexts.org, Molar mass \(\ce{SO_2} = 64.07 \: \text{g/mol}\), \(\Delta H = -198 \: \text{kJ}\) for the reaction of \(2 \: \text{mol} \: \ce{SO_2}\). When \(1 \: \text{mol}\) of calcium carbonate decomposes into \(1 \: \text{mol}\) of calcium oxide and \(1 \: \text{mol}\) of carbon dioxide, \(177.8 \: \text{kJ}\) of heat is absorbed. When fuels burn they release heat energy and light energy to the surroundings in exothermic reactions known as combustion reactions. We will assume that the pressure is constant while the reaction takes place. John T. Moore, EdD, is regents professor of Chemistry at Stephen F. Austin State University, where he is also the director of the Teaching Excellence Center. Calculate heat absorption using the formula: Q = mc T Q means the heat absorbed, m is the mass of the substance absorbing heat, c is the specific heat capacity and T is the change in temperature. Consider Equation \(\ref{5.4.9}\), which describes the reaction of aluminum with iron(III) oxide (Fe2O3) at constant pressure. The heat of reaction, or reaction enthalpy, is an essential parameter to safely and successfully scale-up chemical processes. Assuming all of the heat released by the chemical reaction is absorbed by the calorimeter system, calculate q cal. But they're just as useful in dealing with physical changes, like freezing and melting, evaporating and condensing, and others. During most processes, energy is exchanged between the system and the surroundings. This equation is given . If you're given the amount of energy used, the mass, and initial temperature, here's how to calculate the final temperature of a reaction. For example, if a solution of salt water has a mass of 100 g, a temperature change of 45 degrees and a specific heat of approximately 4.186 joules per gram Celsius, you would set up the following equation -- Q = 4.186(100)(45). You can do this easily: just multiply the heat capacity of the substance youre heating by the mass of the substance and the change in temperature to find the heat absorbed. \[\ce{CaO} \left( s \right) + \ce{CO_2} \left( g \right) \rightarrow \ce{CaCO_3} \left( s \right) + 177.8 \: \text{kJ}\nonumber \]. If more energy is produced in bond formation than that needed for bond breaking, the reaction is exothermic and the enthalpy is negative. Bond breaking ALWAYS requires an input of energy; bond making ALWAYS releases energy.y. Legal. (CC BY-NC-SA; anonymous). The temperature change, along with the specific heat and mass of the solution, can then be used to calculate the amount of heat involved in either case. Learn to use standard heats of formation to calculate standard heats of reaction INTRODUCTION Chemical and physical changes usually involve the absorption or liberation of heat, given the symbol q. The subscript \(p\) is used here to emphasize that this equation is true only for a process that occurs at constant pressure. Then, the change in enthalpy is actually: For more particular problems, we can define the standard enthalpy of formation of a compound, denoted as HfH_\mathrm{f}\degreeHf. All you need to remember for the purpose of this calculator is: Enthalpy, by definition, is the sum of heat absorbed by the system and the work done when expanding: where QQQ stands for internal energy, ppp for pressure and VVV for volume. You must also know its specific heat, or the amount of energy required to raise one gram of the substance 1 degree Celsius. The negative sign associated with \(PV\) work done indicates that the system loses energy when the volume increases. The enthalpy change listed for the reaction confirms this expectation: For each mole of methane that combusts, 802 kJ of heat is released. Second, recall that heats of reaction are proportional to the amount of substance reacting (2 mol of H2O in this case), so the calculation is\r\n\r\n\"Calculating","blurb":"","authors":[{"authorId":9161,"name":"Peter J. Mikulecky","slug":"peter-j-mikulecky","description":"

Christopher Hren is a high school chemistry teacher and former track and football coach. Let's practice our newly obtained knowledge using the above standard enthalpy of formation table. The sign of the, tells you the direction of heat flow, but what about the magnitude? If 17.3 g of powdered aluminum are allowed to react with excess \(\ce{Fe2O3}\), how much heat is produced? Put a solid into water. \[\Delta H = 58.0 \: \text{g} \: \ce{SO_2} \times \dfrac{1 \: \text{mol} \: \ce{SO_2}}{64.07 \: \text{g} \: \ce{SO_2}} \times \dfrac{-198 \: \text{kJ}}{2 \: \text{mol} \: \ce{SO_2}} = 89.6 \: \text{kJ} \nonumber \nonumber \]. For example, stirring a cup of coffee does work in the liquid inside it, and you do work on an object when you pick it up or throw it. In short, the heat capacity tells you how much heat energy (in joules) is needed to raise the temperature of 1 kg of a material by 1 degree C. The specific heat capacity of water is 4,181 J / kg degree C, and the specific heat capacity of lead is 128 J/ kg degree C. This tells you at a glance that it takes less energy to increase the temperature of lead than it does water. If you're given the amount of energy used, the mass, and initial temperature, here's how to calculate the final temperature of a reaction. For example, we have the following reaction: What is the enthalpy change in this case? - q neutralization = q cal The heat of neutralization is the heat evolved (released) when 1 mole of water is produced by the reaction of an acid and base. Dummies has always stood for taking on complex concepts and making them easy to understand. H_{2}O(l) \rightarrow H_{2}O(s) + heat & \Delta H < 0 CHM 120 - Survey of General Chemistry(Neils), { "7.01:_The_Concept_of_Dynamic_Equilibrium" : "property get [Map MindTouch.Deki.Logic.ExtensionProcessorQueryProvider+<>c__DisplayClass228_0.b__1]()", "7.02_The_Equilibrium_Constant" : "property get [Map MindTouch.Deki.Logic.ExtensionProcessorQueryProvider+<>c__DisplayClass228_0.b__1]()", "7.03:_Calculating_the_Equilibrium_Constant_From_Measured_Equilibrium_Concentrations" : "property get [Map MindTouch.Deki.Logic.ExtensionProcessorQueryProvider+<>c__DisplayClass228_0.b__1]()", "7.04_Predicting_the_direction_of_a_reaction" : "property get [Map MindTouch.Deki.Logic.ExtensionProcessorQueryProvider+<>c__DisplayClass228_0.b__1]()", "7.05\\(:\\)__Le_Ch\u00e2telier\u2019s_Principle:_How_a_System_at_Equilibrium_Responds_to_Disturbances" : "property get [Map MindTouch.Deki.Logic.ExtensionProcessorQueryProvider+<>c__DisplayClass228_0.b__1]()", "7.06:_The_First_Law_of_Thermodynamics" : "property get [Map MindTouch.Deki.Logic.ExtensionProcessorQueryProvider+<>c__DisplayClass228_0.b__1]()", "7.07:_Enthalpy:_The_Heat_Evolved_in_a_Chemical_Reaction_at_Constant_Pressure" : "property get [Map MindTouch.Deki.Logic.ExtensionProcessorQueryProvider+<>c__DisplayClass228_0.b__1]()", "7.08_Quantifying_Heat" : "property get [Map MindTouch.Deki.Logic.ExtensionProcessorQueryProvider+<>c__DisplayClass228_0.b__1]()", "7.09:_Entropy_and_the_Second_Law_of_Thermodynamics" : "property get [Map MindTouch.Deki.Logic.ExtensionProcessorQueryProvider+<>c__DisplayClass228_0.b__1]()", "7.10:_Gibbs_Free_Energy" : "property get [Map MindTouch.Deki.Logic.ExtensionProcessorQueryProvider+<>c__DisplayClass228_0.b__1]()", "7.11:_Gibbs_Free_Energy_and_Equilibrium" : "property get [Map MindTouch.Deki.Logic.ExtensionProcessorQueryProvider+<>c__DisplayClass228_0.b__1]()", What_we_are_studying : "property get [Map MindTouch.Deki.Logic.ExtensionProcessorQueryProvider+<>c__DisplayClass228_0.b__1]()" }, { "00:_Front_Matter" : "property get [Map MindTouch.Deki.Logic.ExtensionProcessorQueryProvider+<>c__DisplayClass228_0.b__1]()", "1:_Matter_and_Energy" : "property get [Map MindTouch.Deki.Logic.ExtensionProcessorQueryProvider+<>c__DisplayClass228_0.b__1]()", "2:_Atomic_Structure" : "property get [Map MindTouch.Deki.Logic.ExtensionProcessorQueryProvider+<>c__DisplayClass228_0.b__1]()", "3:_Chemical_Formulas_and_Bonding" : "property get [Map MindTouch.Deki.Logic.ExtensionProcessorQueryProvider+<>c__DisplayClass228_0.b__1]()", "4:_Intermolecular_Forces_Phases_and_Solutions" : "property get [Map MindTouch.Deki.Logic.ExtensionProcessorQueryProvider+<>c__DisplayClass228_0.b__1]()", "5:_The_Numbers_Game_-_Solutions_and_Stoichiometry" : "property get [Map MindTouch.Deki.Logic.ExtensionProcessorQueryProvider+<>c__DisplayClass228_0.b__1]()", "6:_Reaction_Kinetics" : "property get [Map MindTouch.Deki.Logic.ExtensionProcessorQueryProvider+<>c__DisplayClass228_0.b__1]()", "7:_Equilibrium_and_Thermodynamics" : "property get [Map MindTouch.Deki.Logic.ExtensionProcessorQueryProvider+<>c__DisplayClass228_0.b__1]()", "8:_Acids_and_Bases" : "property get [Map MindTouch.Deki.Logic.ExtensionProcessorQueryProvider+<>c__DisplayClass228_0.b__1]()", "9:_Electrochemistry" : "property get [Map MindTouch.Deki.Logic.ExtensionProcessorQueryProvider+<>c__DisplayClass228_0.b__1]()", "zz:_Back_Matter" : "property get [Map MindTouch.Deki.Logic.ExtensionProcessorQueryProvider+<>c__DisplayClass228_0.b__1]()" }, 7.7: Enthalpy: The Heat Evolved in a Chemical Reaction at Constant Pressure, [ "article:topic", "showtoc:no", "license:ccbyncsa", "source-chem-38018", "licenseversion:40" ], https://chem.libretexts.org/@app/auth/3/login?returnto=https%3A%2F%2Fchem.libretexts.org%2FCourses%2FGrand_Rapids_Community_College%2FCHM_120_-_Survey_of_General_Chemistry(Neils)%2F7%253A_Equilibrium_and_Thermodynamics%2F7.07%253A_Enthalpy%253A_The_Heat_Evolved_in_a_Chemical_Reaction_at_Constant_Pressure, \( \newcommand{\vecs}[1]{\overset { \scriptstyle \rightharpoonup} {\mathbf{#1}}}\) \( \newcommand{\vecd}[1]{\overset{-\!-\!\rightharpoonup}{\vphantom{a}\smash{#1}}} \)\(\newcommand{\id}{\mathrm{id}}\) \( \newcommand{\Span}{\mathrm{span}}\) \( \newcommand{\kernel}{\mathrm{null}\,}\) \( \newcommand{\range}{\mathrm{range}\,}\) \( \newcommand{\RealPart}{\mathrm{Re}}\) \( \newcommand{\ImaginaryPart}{\mathrm{Im}}\) \( \newcommand{\Argument}{\mathrm{Arg}}\) \( \newcommand{\norm}[1]{\| #1 \|}\) \( \newcommand{\inner}[2]{\langle #1, #2 \rangle}\) \( \newcommand{\Span}{\mathrm{span}}\) \(\newcommand{\id}{\mathrm{id}}\) \( \newcommand{\Span}{\mathrm{span}}\) \( \newcommand{\kernel}{\mathrm{null}\,}\) \( \newcommand{\range}{\mathrm{range}\,}\) \( \newcommand{\RealPart}{\mathrm{Re}}\) \( \newcommand{\ImaginaryPart}{\mathrm{Im}}\) \( \newcommand{\Argument}{\mathrm{Arg}}\) \( \newcommand{\norm}[1]{\| #1 \|}\) \( \newcommand{\inner}[2]{\langle #1, #2 \rangle}\) \( \newcommand{\Span}{\mathrm{span}}\)\(\newcommand{\AA}{\unicode[.8,0]{x212B}}\). As with other stoichiometry problems, the moles of a reactant or product can be linked to mass or volume. stoichiometric coefficient. Since \(198 \: \text{kJ}\) is released for every \(2 \: \text{mol}\) of \(\ce{SO_2}\) that reacts, the heat released when about \(1 \: \text{mol}\) reacts is one half of 198. For example, let's look at the reaction Na+ + Cl- NaCl. We believe everyone should have free access to Physics educational material, by sharing you help us reach all Physics students and those interested in Physics across the globe. The heat of reaction is the energy that is released or absorbed when chemicals are transformed in a chemical reaction. If the system loses a certain amount of energy, that same amount of energy is gained by the surroundings. refers to the enthalpy change for one mole equivalent of the reaction. The change in enthalpy that occurs when a specified amount of solute dissolves in a given quantity of solvent. But before that, you may ask, "How to calculate standard enthalpy of formation for each compound?" Calculate the enthalpy change that occurs when \(58.0 \: \text{g}\) of sulfur dioxide is reacted with excess oxygen. As long as you use consistent units, the formula above will hold. (Use 4.184 J g 1 C 1 as the specific . But an element formed from itself means no heat change, so its enthalpy of formation will be zero. The sign of \(\Delta H\) is negative because the reaction is exothermic. Legal. A chemical reaction or physical change is endothermic if heat is absorbed by the system from the surroundings. She has acted as a copywriter and screenplay consultant for Advent Film Group and as a promotional writer for Cinnamom Bakery. In thermodynamics, internal energy (also called the thermal energy) is defined as the energy associated with microscopic forms of energy.It is an extensive quantity, it depends on the size of the system, or on the amount of substance it contains.The SI unit of internal energy is the joule (J).It is the energy contained within the system, excluding the kinetic energy of motion . If you seal the end of a syringe and push on the plunger, is that process isothermal? As an example, imagine increasing the temperature of 2 kg of water from 10 degrees C to 50 degrees C. The change in temperature is T = (50 10) degrees C = 40 degrees C. From the last section, the specific heat capacity of water is 4,181 J / kg degree C, so the equation gives: Q = 2 kg 4181 J / kg degree C 40 degrees C. So it takes about 334.5 thousand joules (kJ) of heat to raise the temperature of 2 kg of water by 40 degrees C. Sometimes specific heat capacities are given in different units. It is the change in internal energy that produces heat plus work. Simplify the equation. Therefore We have the formula, Therefore, Q = 1672 J Physics Formulas Customize your course in 30 seconds The heat flow for a reaction at constant pressure, q p, is called enthalpy, H. Although laymen often use the terms "heat" and "temperature" interchangeably, these terms describe different measurements. For example, when an exothermic reaction occurs in solution in a calorimeter, the heat produced by the reaction is absorbed by the solution, which increases its temperature. As you enter the specific factors of each heat absorbed or released calculation, the Heat Absorbed Or Released Calculator will automatically calculate the results and update the Physics formula elements with each element of the heat absorbed or released calculation. H = H of products - H of reactants . After mixing 100.0 g of water at 58.5 C with 100.0 g of water, already in the calorimeter, at 22.8 C, the final temperature of the water is 39.7 C. Find the solution's specific heat on a chart or use the specific heat of water, which is 4.186 joules per gram Celsius. The chemical equation of the reaction is: $$\ce {NaOH (s) +H+ (aq) + Cl- (aq) -> Na+ (aq) +Cl- (aq) + H2O (l)}$$ This is the ONLY information I can use and I cannot search up anything online. Find the solution's specific heat on a chart or use the specific heat of water, which is 4.186 joules per gram Celsius. General Chemistry: Principles & Modern Applications. The standard enthalpy of formation formula for a reaction is as follows: If you're paying attention, you might have observed that Hf(products)H_\mathrm{f}\degree(\mathrm{products})Hf(products) and Hf(reactants)H_\mathrm{f}\degree(\mathrm{reactants})Hf(reactants) have different units than HreactionH\degree_\mathrm{reaction}Hreaction. Roughly speaking, the change in enthalpy in a chemical reaction equals the amount of energy lost or gained during the reaction. Find the enthalpy of Na+ ( -240.12 kJ) and Cl- ( -167.16 kJ ). Subjects: Chemistry. It is important to include the physical states of the reactants and products in a thermochemical equation as the value of the \(\Delta H\) depends on those states. Figure out . Let's assume the formation of water, H2O, from hydrogen gas, H2, and oxygen gas, O2. Based on the stoichiometry of the equation, you can also say that 802 kJ of heat is released for every 2 mol of water produced. Subtract the mass of the empty container from the mass of the full container to determine the mass of the solution. \"https://sb\" : \"http://b\") + \".scorecardresearch.com/beacon.js\";el.parentNode.insertBefore(s, el);})();\r\n","enabled":true},{"pages":["all"],"location":"footer","script":"\r\n

\r\n","enabled":false},{"pages":["all"],"location":"header","script":"\r\n","enabled":false},{"pages":["article"],"location":"header","script":" ","enabled":true},{"pages":["homepage"],"location":"header","script":"","enabled":true},{"pages":["homepage","article","category","search"],"location":"footer","script":"\r\n\r\n","enabled":true}]}},"pageScriptsLoadedStatus":"success"},"navigationState":{"navigationCollections":[{"collectionId":287568,"title":"BYOB (Be Your Own Boss)","hasSubCategories":false,"url":"/collection/for-the-entry-level-entrepreneur-287568"},{"collectionId":293237,"title":"Be a Rad Dad","hasSubCategories":false,"url":"/collection/be-the-best-dad-293237"},{"collectionId":295890,"title":"Career Shifting","hasSubCategories":false,"url":"/collection/career-shifting-295890"},{"collectionId":294090,"title":"Contemplating the Cosmos","hasSubCategories":false,"url":"/collection/theres-something-about-space-294090"},{"collectionId":287563,"title":"For Those Seeking Peace of Mind","hasSubCategories":false,"url":"/collection/for-those-seeking-peace-of-mind-287563"},{"collectionId":287570,"title":"For the Aspiring Aficionado","hasSubCategories":false,"url":"/collection/for-the-bougielicious-287570"},{"collectionId":291903,"title":"For the Budding Cannabis Enthusiast","hasSubCategories":false,"url":"/collection/for-the-budding-cannabis-enthusiast-291903"},{"collectionId":291934,"title":"For the Exam-Season Crammer","hasSubCategories":false,"url":"/collection/for-the-exam-season-crammer-291934"},{"collectionId":287569,"title":"For the Hopeless Romantic","hasSubCategories":false,"url":"/collection/for-the-hopeless-romantic-287569"},{"collectionId":296450,"title":"For the Spring Term Learner","hasSubCategories":false,"url":"/collection/for-the-spring-term-student-296450"}],"navigationCollectionsLoadedStatus":"success","navigationCategories":{"books":{"0":{"data":[{"categoryId":33512,"title":"Technology","hasSubCategories":true,"url":"/category/books/technology-33512"},{"categoryId":33662,"title":"Academics & The Arts","hasSubCategories":true,"url":"/category/books/academics-the-arts-33662"},{"categoryId":33809,"title":"Home, Auto, & Hobbies","hasSubCategories":true,"url":"/category/books/home-auto-hobbies-33809"},{"categoryId":34038,"title":"Body, Mind, & Spirit","hasSubCategories":true,"url":"/category/books/body-mind-spirit-34038"},{"categoryId":34224,"title":"Business, Careers, & Money","hasSubCategories":true,"url":"/category/books/business-careers-money-34224"}],"breadcrumbs":[],"categoryTitle":"Level 0 Category","mainCategoryUrl":"/category/books/level-0-category-0"}},"articles":{"0":{"data":[{"categoryId":33512,"title":"Technology","hasSubCategories":true,"url":"/category/articles/technology-33512"},{"categoryId":33662,"title":"Academics & The Arts","hasSubCategories":true,"url":"/category/articles/academics-the-arts-33662"},{"categoryId":33809,"title":"Home, Auto, & Hobbies","hasSubCategories":true,"url":"/category/articles/home-auto-hobbies-33809"},{"categoryId":34038,"title":"Body, Mind, & Spirit","hasSubCategories":true,"url":"/category/articles/body-mind-spirit-34038"},{"categoryId":34224,"title":"Business, Careers, & Money","hasSubCategories":true,"url":"/category/articles/business-careers-money-34224"}],"breadcrumbs":[],"categoryTitle":"Level 0 Category","mainCategoryUrl":"/category/articles/level-0-category-0"}}},"navigationCategoriesLoadedStatus":"success"},"searchState":{"searchList":[],"searchStatus":"initial","relatedArticlesList":[],"relatedArticlesStatus":"initial"},"routeState":{"name":"Article3","path":"/article/academics-the-arts/science/chemistry/how-to-calculate-endothermic-and-exothermic-reactions-143396/","hash":"","query":{},"params":{"category1":"academics-the-arts","category2":"science","category3":"chemistry","article":"how-to-calculate-endothermic-and-exothermic-reactions-143396"},"fullPath":"/article/academics-the-arts/science/chemistry/how-to-calculate-endothermic-and-exothermic-reactions-143396/","meta":{"routeType":"article","breadcrumbInfo":{"suffix":"Articles","baseRoute":"/category/articles"},"prerenderWithAsyncData":true},"from":{"name":null,"path":"/","hash":"","query":{},"params":{},"fullPath":"/","meta":{}}},"dropsState":{"submitEmailResponse":false,"status":"initial"},"sfmcState":{"status":"initial"},"profileState":{"auth":{},"userOptions":{},"status":"success"}}.